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Friday, March 1, 2013

Weekend Assignment 3/1

Howdy, y'all.

Please watch the following video from Khan Academy to prepare for Monday's lesson. (Don't forget to click "full screen" so you can see! Your drill question will be:

What is a rational number?

Then, you will need to provide an example of a rational number.




Monday, February 18, 2013

Tuesday, 2/19

First of all, let me thank all of you for the super-awesome, very thoughtful cards I received from each of you. They were such a blessing to read. I can't wait to get back to school!

Today is a game day :) Visit http://www.sheppardsoftware.com/math.htm and try the games under "Fractions". Equivalent Fractions Matching, Reduce Fractions Shoot and Equivalent Fractions Mathman (this one uses the keyboard from my computer) are great ones to start with. They involve finding equivalent fractions and simplifying fractions. You may use a calculator. Please take turns.

Have fun!

Thursday, February 14, 2013

Thursday 2/14

Happy Valentine's Day! Did anyone else get snow last night??? :)

Today we move along in 4-4 to "Simplifying Fractions" - pgs. 196 - 197. To simplify a fraction:
1) Find the GCF of the numerator and denominator (don't worry, you can just use the regular ol' listing method for now to find the GCF)
2) Divide the numerator and denominator by the GCF for your simplified fraction

*Skip over Example 3 on pg. 197 - this requires you to understand polynomials & GCF, which we need to travel back to*

Try pg. 198, 7 - 12 and 28 - 31, 40, 42, and 48. 

Enjoy your long weekend!

Tuesday, February 12, 2013

Wednesday 2/13

Well, folks... after much debate... I think we're going to save 4-3 for when I return. For now let's move ahead with some easier stuff, and then we'll come back to polynomials.

Today's assignment:

1) Read "Finding Equivalent Fractions" on pg. 196.
Notice that, in order to find an equivalent fraction, all you have to do is multiply or divide both the top and bottom numbers by the same number. 

For example:
If we need to find an equivalent fraction to 2/3, we can multiply both the top and bottom numbers by the same thing to get an equivalent fraction. Let's use "4."
If we multiply the top number (2) by 4, we get 8. If we multiply the bottom number (3) by 4, we get 12. So our new fraction is 8/12. This means that 2/3 = 8/12 (they are equivalent fractions).
Here's a visual from imoamal.org - notice that the same amount of "pie" is covered by both fractions, which means they are equivalent:


2) Watch the following video on KA:
https://www.khanacademy.org/math/arithmetic/fractions/Equivalent_fractions/v/equivalent-fractions

3) Complete a, b, and c under Example 1 on pg. 196 AND 1 - 6 on pg. 198.

Happy Math-ing.

PS - Roscoe says, "Let it Snow!"

Monday, February 11, 2013

Another Tuesday Post

If you're reading this it means you've already gone through the other blog post for today and checked your answers for Friday's questions along with the step-by-step pictures.

P.S. - Roscoe says hello:


Now that we (hopefully) have a good understanding of how to find the GCF of two numbers by using prime factorization, let's take a look at polynomials.

First, let me explain what a polynomial is. A polynomial is an algebraic expression with more than one term. We did a lot with polynomials back when we were simplifying expressions. 3ab is a polynomial - it says "3 times a times b" because they're all right next to each other. 6a3b and 4a2b are also polynomials. 

So... what does this have to do with GCF, you might ask? We're going to be finding the GCF for polynomials, using prime factorization, just like we did with regular numbers.

Let's take those two polynomials from above (in red) and first find the prime factorization of each. We do this by breaking down any regular numbers in the polynomial into its prime factor. Then, for all the variables, just write them out (take them out of exponential form):
It's kinda like take a puzzle apart. Now, the second polynomial:

 Now we can compare the two prime factorizations:

We have a few matches. One 2 on both sides, 2 a's on both sides, and a b on both sides. Multiply your matches together, and now we have the GCF:
The GCF = 2a2b

This example is also given in your textbooks on pg. 191. 
Please watch the following video from Khan Academy only until 2:31:



As usual, if you have any questions please leave me a comment. Using this information try pg. 193, 21 - 24 and 37 - 40. Please turn in what you have to your sub. 


Sunday, February 10, 2013

Tuesday 2/12

Hello all. Just a quick note about showing work - please remember to show your work by hand. While a few of you got all of the answers correct for the blog questions from Friday, I didn't see any of your work, and was not able to tell if you found those answers by using the prime factorization method or the listing method.

Right now, it's important that you're using the prime factorization method specifically so that we can move on to the next step.

If you finished your work Friday, it will be passed back to you with comments I've made. If not, please take it out. Everyone should compare their work from Friday to the answers on today's blog. Let's take a look at how we can find the GCF of each set of numbers by using the prime factorization method:

1)  16, 60

First, find the prime factorization of each:
Next, identify the matches on each side. A "match" is when there's a number on one side (at the bottom of the tree) that has an EXACT twin on the other side. The two numbers team up to create a "match."
We have underlined our matches. There's a "2" on one side, and another "2" on the other side. This gives us our first match: 2. Our second match is also 2, since there is a second two on both sides. As shown in the picture below, the remaining numbers have no matches:
Now, list our matches. We have one match of "2" and another match of "2". We multiply our matches together:
The GCF = 4.


Let's look @ #2 from yesterday's blog:

2)  36, 81

Step 1: Find the prime factorization of both numbers. Then, find your matches:
The 1st 3 on the left side matches with the 1st 3 on the right side. This gives us our first match of "3." The next 3 on the left side matches with the second 3 on the right side. This gives us another match of "3." None of the other numbers have matches. So, our matches are 3 and 3. Now, we multiply our matches to get a GCF of 9:


3)  15, 30
Here's one big diagram that puts everything together (click the pic to make it bigger):


4)  32, 64
We had five 2s on the left side, which all had matches on the right side. So our matches are 2, 2, 2, 2, and 2:


5)  10, 13 --- Don't forget that every number has a factor of "1":

That was a tricky one :). Now we need more practice. Your classwork today will be collected. Please hand in Friday's work as well if you have not already done so. I will be checking for work shown - this is the most important part, so I can help you when you make a mistake.
Let's try the following five problems. Same directions as Friday - find the GCF of each pair of numbers using the prime factorization method. 

1)   18, 24
2)   36, 54
3)   75, 100
4)   24, 36
5)   30, 90

Thursday, February 7, 2013

Friday's Class

Hmmm... I wonder if you'll be reading this on Friday, or Monday? Since we're supposed to get some .:snow:.! :)

Okay. Let's get down to business with these GCF things.

Here are the answers from yesterday's assignment (pg. 193, 17 - 24). I know they were very difficult so please don't worry if you got them wrong. I wanted to let you try them first though after reading the textbook:

17.  5
18.  7
19.  25
20.  3
21.  7c
22.  3y2
23.  6c3
24.  2mn




Before we can really tackle finding the GCF for those complicated variable expressions, we need to master the "hard" way of finding a GCF.

As we learned yesterday, we can find the GCF of two numbers two different ways. First, by listing the factors, and identifying the biggest one they have in common. 


Example:
Find the GCF of 30 and 18. 
If we list the factors of 30, we get: 1, 2, 3, 5, 6, 10, 15, and 30. 
If we list the factors of 18, we get: 1, 2, 3, 6, 9, and 18. 
When we compare the two lists, we see that the greatest common factor shared by both of them is 6. 

This method is easiest with relatively small numbers. 

Let's look at the other way. 

To find the GCF of two numbers by using prime factorization, first do factor trees for the two numbers. 

                     30                              18
                  2  x  15                      2  x  9   
               2  x  3  x  5                2  x  3  x  3
The prime factorizations for both numbers are, as usual, @ the bottom of the tree. 

Now here's where it gets tricky. After this step, identify all of the common factors @ the bottom of the trees. The thing is, each common (or "shared") factor has to have a match!

We see that both sides have one 2. So we can select 2 as a common factor. Only one side has a 5, so we cannot use the 5 as a common factor. Both sides have one 3, so we can select 3 as a common factor. Now, look on the side for 18. We have an extra 3 hanging around at the bottom. The thing is, that 3 doesn't have a match on the other side. No twin, no bff, no match. So the extra 3 is not a "common" factor. 

Follow me so far? We've identified the common factors at the bottom of each tree to be 2 and 3. Now we multiply those common factors together: 2 x 3. We get 6. Now we know that 6 is the GCF of 30 and 18. 

Let's stop here and practice the method of finding the GCF using prime factorization without worrying about polynomials, variables, exponents, etc. We're going to break it down step-by-step. 

Try the following 5 problems individually using the prime factorization method. Find the GCF:

1)  16, 60

2)  36, 81

3)  15, 30

4)  32, 64

5)  10, 13 ---> This is a tricky one! Can anyone figure it out? :)